10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount of water produced in this reaction will be
(a) 1 mol
(b) 2 mol
(c) 3 mol
(d) 4 mol
2H2 + O2 2H2O
4 g 32 g 2 moles
4g of H2 require 32 g of O2.
So, 10 g of H2 will require = = 80 g
In the question, as 10 g of H2 is to react with 64 g of O2
So, O2 will completely consumed and will act as limiting reagent.
32 g of O2 gives H2O = 2 mol
64 g of O2 gives H2O = = 4 mol
Option (d) is correct