Home | Chemistry | Physical Chemistry | Some Basic Concepts | Limiting Reagent And Yield | Mcq | Find The Volume Of Co Required To Reduce 025 Mole Ferric Oxide As Per The Given Equationa 168 Dm3b 672nbspdm3c 224nbspdm3d 448nbspdm3

MCQ

Limiting Reagent and Yield
By Sakshi Goel | 19 May'20 | 1 K Views

MCQ

Problem:

Find the volume of CO required to reduce 0.25 mole ferric oxide as per the given equation
Fe subscript 2 O subscript 3 and 3 C O yields 2 Fe and 3 C O subscript 2
(a) 16.8 dm3
(b) 67.2 dm3
(c) 22.4 dm3
(d) 44.8 dm3


Solution:

In the reaction, 1 mole of ferric oxide reacts with 3 moles of CO.
So, 0.25 mole of ferric oxide reacts with moles of CO = 3(0.25) = 0.75 mol
Volume of 1 mole = 22.4 L
Volume of 0.75 mol = 22.4 x 0.75 = 16.8 L
1 L = 1 dm3
So, 16.8 L = 16.8 dm3
Correct option is (a).


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