MCQ

Limiting Reagent and Yield

By Sakshi Goel | 19 May'20 | 1 K Views

MCQ

Problem:
In the reaction $4 A + 2 B + 3 C â†’ A_{4} B_{2} C_{3}$ , what will be the number of moles of product formed when we started with 1 mole A, 0.6 mol B and 0.72 mol C?
(a) 0.25
(b) 0.24
(c) 0.3
(d) 2.32

Solution:

In the reaction, to check the limiting reagent,

	A	B	C
In reaction	4 moles	2 moles	3 moles
Question	1 mole	$\frac{2}{4} Ã— 1 = 0.5 m o l$	$\frac{3}{4} Ã— 1 = 0.75 m o l$

But we have 0.72 mol C, so C is the limiting reagent.
For 3 moles of C, we get 1 mole of product,
if we have 0.72 mol of C, then moles of product formed will be = $\frac{1}{3} Ã— 0.72 = 0.24 m o l$
Correct option is (b).

Problem: For the reaction,
$4 {NH}_{3} + 5 O_{2} â†’ 4 NO + 6 H_{2} O$

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