Number of electrons present in 1.6 g of methane is
(a) 6.02 x 1024
(b) 6.02 x 1023
(c) 6.02 x 1022
(d) 6.02 x 1021
1 mole of methane = 16 g = 6.02 x 1023 molecules of CH4
1.6 g = (1.6/16) x 6.02 x 1023 = 6.02 x 1022 molecules of CH4
C has 6 electrons and H has 1 electron.
In total, 1 molecule of CH4 has 10 electrons.
So, 6.02 x 1022 molecules of CH4 will have 6.02 x 1022