MCQ

Mole Concept

By Sakshi Goel | 22 May'20 | 951 Views

Problem:
The total number of electrons in 1.6 g of CH₄ to that in 1.8 g of H₂O
(a) Double
(b) Same
(c) Triple
(d) One fourth

Solution:

Avogadro number = N_o

_{Total number of e}^__{in CH₄ = 10}

Number of e^â€“ in 1.6 g of CH₄ = $\frac{1.6}{16} Ã— 10 Ã— N_{o}$ = N_o

_{Total number of e}^__{in H₂O = 10}

Number of e^â€“ in 1.8 g of H₂O = $\frac{1.8}{18} Ã— 10 Ã— N_{o}$ = N_o

So, correct option is (b).

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