Home | Chemistry | Physical Chemistry | Some Basic Concepts | Mole Concept | Mcq | Volume Of Oxygen At Ntp Required To Completely Burn 1 Kg Of Coal 100 Carbon Isa 224 Lb 186 X 103 Lc 224 X 103 Ld 1000 L

MCQ

Mole Concept
By Sakshi Goel | 18 May'20 | 531 Views

MCQ

Problem:

Volume of oxygen at NTP, required to completely burn 1 kg of coal (100 % carbon) is
(a) 22.4 L
(b) 1.86 x 103 L
(c) 22.4 x 103 L
(d) 1000 L


Solution:

The equation for reaction of coal with oxygen during burning is
C space plus space O subscript 2 space end subscript yields space C O subscript 2
1 mole of C reacts with 1 mole of O2.
Mass of coal = 1 kg = 1000 g
Molar mass of C = 12 g/mol
Moles of C = mass/molar mass = 1000/12 = 83.3 mol
83.3 moles of carbon will react with 83.3 moles of oxygen.
At NTP, 1 mol = 22.4 L
83.3 moles = 22.4 x 83.3 = 1866 L = 1.86 x 103 L
Option (b) is correct.


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