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Mole Concept

By Sakshi Goel | 24 May'20 | 520 Views

Short Answer

Problem:
Haemoglobin contains 0.334% of iron by weight. The molecular weight of haemoglobin is approximately 67200.
Calculate the number of iron atoms (Atomic weight of Fe is 56) present in one molecule of haemoglobin.

Solution:

Weight of Fe in haemoglobin = $\frac{0.334}{100} Ã— 67200$ = 224.48 g
Mass of one Fe atom = 56 g
Total number of Fe atom = $\frac{224.48}{56}$ = 4

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