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SHORTANSWER

Mole Concept
By Sakshi Goel | 22 May'20 | 527 Views

Short Answer

Problem:

What is the volume occupied by one molecule of water (density = 1 g cm-3)?


Solution:

As water is liquid its density = 1 g/mL
i.e., 1 g of H2O have volume = 1 mL
Mass of one molecule = fraction numerator 18 over denominator 6.02 cross times 10 to the power of 23 end fraction g
fraction numerator 18 over denominator 6.02 cross times 10 to the power of 23 end fraction g of H2O have volume = fraction numerator 18 over denominator 6.02 cross times 10 to the power of 23 end fractionmL = 3.0 × 10-23 mL


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