MCQ
Percentage Composition
By Sakshi Goel | 19 May'20 | 1 K Views
MCQ
Problem:
Solution:
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1.24 g ‘P’ is present in 2.2 g of
(a) P2S4
(b) P2S2
(c) P4S3
(d) PS2
Solution:
If 1.24 g of P is present in 2.2 g of compound, % of P = (1.24/2.2) x 100 = 56.4 %
In option (a), P2S4, molar mass = 190 g/mol, total P present = 62 g/mol
% P = (62/190) x 100 = 32.6 %
In option (b), P2S2, molar mass = 126 g/mol, total P present = 62 g/mol
% P = (62/126) x 100 = 49.2 %
In option (c), P4S3, molar mass = 220 g/mol, total P present = 124 g/mol
% P = (124/220) x 100 = 56.4 %
In option (d), PS2, molar mass = 95 g/mol, total P present = 31 g/mol
% P = (31/95) x 100 = 32.6 %
Correct option is (c)
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