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Percentage Composition

By Sakshi Goel | 22 May'20 | 915 Views

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Problem:
An element, X has the following isotopic composition ²⁰⁰X : 90%, ¹⁹⁹X : 8%, and ²⁰²X : 2.0%. What is the weighted average atomic mass of the naturally occurring element X?

Solution:

$A v e r a g e a t o m i c m a s s = \frac{{âˆ‘}_{}^{} p e r c e n t a g e Ã— a t o m i c m a s s}{100}$

$= \frac{(200 Ã— 90) + (199 Ã— 8) + (202 Ã— 2.0)}{100}$

= 200 amu

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